Optimal. Leaf size=321 \[ -\frac{\left (a^2-9 a b-2 b^2\right ) \sin (e+f x) \cos (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 b f}+\frac{a (a+b) \left (2 a^2+9 a b-b^2\right ) \sqrt{\cos ^2(e+f x)} \sec (e+f x) \sqrt{\frac{b \sin ^2(e+f x)}{a}+1} F\left (\sin ^{-1}(\sin (e+f x))|-\frac{b}{a}\right )}{35 b^2 f \sqrt{a+b \sin ^2(e+f x)}}-\frac{2 (a-b) \left (a^2+6 a b+b^2\right ) \sqrt{\cos ^2(e+f x)} \sec (e+f x) \sqrt{a+b \sin ^2(e+f x)} E\left (\sin ^{-1}(\sin (e+f x))|-\frac{b}{a}\right )}{35 b^2 f \sqrt{\frac{b \sin ^2(e+f x)}{a}+1}}-\frac{b \sin (e+f x) \cos ^5(e+f x) \sqrt{a+b \sin ^2(e+f x)}}{7 f}+\frac{2 (4 a+b) \sin (e+f x) \cos ^3(e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 f} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.389175, antiderivative size = 321, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.32, Rules used = {3192, 416, 528, 524, 426, 424, 421, 419} \[ -\frac{\left (a^2-9 a b-2 b^2\right ) \sin (e+f x) \cos (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 b f}+\frac{a (a+b) \left (2 a^2+9 a b-b^2\right ) \sqrt{\cos ^2(e+f x)} \sec (e+f x) \sqrt{\frac{b \sin ^2(e+f x)}{a}+1} F\left (\sin ^{-1}(\sin (e+f x))|-\frac{b}{a}\right )}{35 b^2 f \sqrt{a+b \sin ^2(e+f x)}}-\frac{2 (a-b) \left (a^2+6 a b+b^2\right ) \sqrt{\cos ^2(e+f x)} \sec (e+f x) \sqrt{a+b \sin ^2(e+f x)} E\left (\sin ^{-1}(\sin (e+f x))|-\frac{b}{a}\right )}{35 b^2 f \sqrt{\frac{b \sin ^2(e+f x)}{a}+1}}-\frac{b \sin (e+f x) \cos ^5(e+f x) \sqrt{a+b \sin ^2(e+f x)}}{7 f}+\frac{2 (4 a+b) \sin (e+f x) \cos ^3(e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 f} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 3192
Rule 416
Rule 528
Rule 524
Rule 426
Rule 424
Rule 421
Rule 419
Rubi steps
\begin{align*} \int \cos ^4(e+f x) \left (a+b \sin ^2(e+f x)\right )^{3/2} \, dx &=\frac{\left (\sqrt{\cos ^2(e+f x)} \sec (e+f x)\right ) \operatorname{Subst}\left (\int \left (1-x^2\right )^{3/2} \left (a+b x^2\right )^{3/2} \, dx,x,\sin (e+f x)\right )}{f}\\ &=-\frac{b \cos ^5(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{7 f}-\frac{\left (\sqrt{\cos ^2(e+f x)} \sec (e+f x)\right ) \operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^{3/2} \left (-a (7 a+b)-2 b (4 a+b) x^2\right )}{\sqrt{a+b x^2}} \, dx,x,\sin (e+f x)\right )}{7 f}\\ &=\frac{2 (4 a+b) \cos ^3(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 f}-\frac{b \cos ^5(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{7 f}-\frac{\left (\sqrt{\cos ^2(e+f x)} \sec (e+f x)\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1-x^2} \left (-3 a b (9 a+b)+3 b \left (a^2-9 a b-2 b^2\right ) x^2\right )}{\sqrt{a+b x^2}} \, dx,x,\sin (e+f x)\right )}{35 b f}\\ &=-\frac{\left (a^2-9 a b-2 b^2\right ) \cos (e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 b f}+\frac{2 (4 a+b) \cos ^3(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 f}-\frac{b \cos ^5(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{7 f}-\frac{\left (\sqrt{\cos ^2(e+f x)} \sec (e+f x)\right ) \operatorname{Subst}\left (\int \frac{-3 a b \left (a^2+18 a b+b^2\right )+6 (a-b) b \left (a^2+6 a b+b^2\right ) x^2}{\sqrt{1-x^2} \sqrt{a+b x^2}} \, dx,x,\sin (e+f x)\right )}{105 b^2 f}\\ &=-\frac{\left (a^2-9 a b-2 b^2\right ) \cos (e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 b f}+\frac{2 (4 a+b) \cos ^3(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 f}-\frac{b \cos ^5(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{7 f}+\frac{\left (a (a+b) \left (2 a^2+9 a b-b^2\right ) \sqrt{\cos ^2(e+f x)} \sec (e+f x)\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x^2} \sqrt{a+b x^2}} \, dx,x,\sin (e+f x)\right )}{35 b^2 f}-\frac{\left (2 (a-b) \left (a^2+6 a b+b^2\right ) \sqrt{\cos ^2(e+f x)} \sec (e+f x)\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a+b x^2}}{\sqrt{1-x^2}} \, dx,x,\sin (e+f x)\right )}{35 b^2 f}\\ &=-\frac{\left (a^2-9 a b-2 b^2\right ) \cos (e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 b f}+\frac{2 (4 a+b) \cos ^3(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 f}-\frac{b \cos ^5(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{7 f}-\frac{\left (2 (a-b) \left (a^2+6 a b+b^2\right ) \sqrt{\cos ^2(e+f x)} \sec (e+f x) \sqrt{a+b \sin ^2(e+f x)}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1+\frac{b x^2}{a}}}{\sqrt{1-x^2}} \, dx,x,\sin (e+f x)\right )}{35 b^2 f \sqrt{1+\frac{b \sin ^2(e+f x)}{a}}}+\frac{\left (a (a+b) \left (2 a^2+9 a b-b^2\right ) \sqrt{\cos ^2(e+f x)} \sec (e+f x) \sqrt{1+\frac{b \sin ^2(e+f x)}{a}}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x^2} \sqrt{1+\frac{b x^2}{a}}} \, dx,x,\sin (e+f x)\right )}{35 b^2 f \sqrt{a+b \sin ^2(e+f x)}}\\ &=-\frac{\left (a^2-9 a b-2 b^2\right ) \cos (e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 b f}+\frac{2 (4 a+b) \cos ^3(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 f}-\frac{b \cos ^5(e+f x) \sin (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{7 f}-\frac{2 (a-b) \left (a^2+6 a b+b^2\right ) \sqrt{\cos ^2(e+f x)} E\left (\sin ^{-1}(\sin (e+f x))|-\frac{b}{a}\right ) \sec (e+f x) \sqrt{a+b \sin ^2(e+f x)}}{35 b^2 f \sqrt{1+\frac{b \sin ^2(e+f x)}{a}}}+\frac{a (a+b) \left (2 a^2+9 a b-b^2\right ) \sqrt{\cos ^2(e+f x)} F\left (\sin ^{-1}(\sin (e+f x))|-\frac{b}{a}\right ) \sec (e+f x) \sqrt{1+\frac{b \sin ^2(e+f x)}{a}}}{35 b^2 f \sqrt{a+b \sin ^2(e+f x)}}\\ \end{align*}
Mathematica [A] time = 2.6002, size = 247, normalized size = 0.77 \[ \frac{\sqrt{2} b \sin (2 (e+f x)) \left (b \left (144 a^2-192 a b-37 b^2\right ) \cos (2 (e+f x))+400 a^2 b-32 a^3+2 b^2 (b-26 a) \cos (4 (e+f x))+212 a b^2+5 b^3 \cos (6 (e+f x))+30 b^3\right )+64 a \left (11 a^2 b+2 a^3+8 a b^2-b^3\right ) \sqrt{\frac{2 a-b \cos (2 (e+f x))+b}{a}} F\left (e+f x\left |-\frac{b}{a}\right .\right )-128 a \left (5 a^2 b+a^3-5 a b^2-b^3\right ) \sqrt{\frac{2 a-b \cos (2 (e+f x))+b}{a}} E\left (e+f x\left |-\frac{b}{a}\right .\right )}{2240 b^2 f \sqrt{2 a-b \cos (2 (e+f x))+b}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 1.266, size = 590, normalized size = 1.8 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sin \left (f x + e\right )^{2} + a\right )}^{\frac{3}{2}} \cos \left (f x + e\right )^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-{\left (b \cos \left (f x + e\right )^{6} -{\left (a + b\right )} \cos \left (f x + e\right )^{4}\right )} \sqrt{-b \cos \left (f x + e\right )^{2} + a + b}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \sin \left (f x + e\right )^{2} + a\right )}^{\frac{3}{2}} \cos \left (f x + e\right )^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]